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The match will be $& unless you use look-before and look-behind (unsure whether using those will actually save any memory); if you are interested in just a part of the match, use a capturing group. How to match, but not capture, part of a regex? - Stack Overflow You can match directly against the type of v, but you need a value pattern to refer to the types to match, as a "dotless" name is a capture pattern that matches any value. When I compile the Python code below, I get IndentationError: unindent does not match any outer indentation level import sys def Factorial(n): # Return factorial result = 1 for i in range... the value of the attribute, matched by almost anything: (.*?); in this specific syntax, using the greedy match (the question mark after the asterisk) the RegExp engine enables a "look-ahead"-like operator, which matches anything but what follows this sub-expression
Regex symbol to match at beginning of a line: ^ Add the string you're searching for (CTR) to the regex like this: ^CTR Example: regex That should be enough! However, if you need to get the text from the whole line in your language of choice, add a "match anything" pattern .*: ^CTR.* Example: more regex If you want to get crazy, use the end of line matcher $ Add that to the growing regex ... This MATLAB function returns the starting index of each substring of str that matches the character patterns specified by the regular expression.
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